

An Introduction to Wurtz–Fittig Reaction
Carbon is probably the most important compound in the whole periodic table, versatile for everything and the forming basics of every chemical science. With the help of this tetravalent and unique compound, the Wurtz–Fittig reaction was discovered.
In the year 1855, Charles Adolphe Wurtz found the reaction called the Wurtz reaction. The reaction involved a new carbon–carbon which is followed up by a coupling reaction between two alkyl halides.
This was further extended by another scientist, Wilhelm Rudolph Fitting, in the year 1860. Hence, the reaction is later known as the Wurtz–Fittig reaction.
Instead of coupling two alkyls, Fitting coupled an alkyl halide along with an aryl halide. The reaction best works for asymmetric products. It is one of the important reactions of organic chemistry which is used to synthesise carbon–carbon bonds.
Let us discuss them in further detail.
Aryl halide reacts with alkyl halide with sodium metal in presence of dry ether to form alkyl substituted benzene.
In this reaction, ethane and biphenyl are also formed in small amounts.
What is Wurtz–Fittig Reaction?
The reaction of an alkyl halide with aryl halide and sodium metal in presence of dry ether to form substituted aromatic compounds by the formation of new carbon–carbon bond is called Wurtz–Fittig reaction. The reaction is given below – It is a coupling reaction. It is a modified form of Wurtz reaction. Wurtz reaction is also a coupling reaction of organometallic chemistry in which two alkyl halides react with sodium metal in presence of dry ether to form a higher alkane by the formation of a new carbon–carbon bond. Wurtz Reaction is given below –
2R – X + 2Na → R – R + 2NaX
Where R = alkyl group
X = Halide ion
Wurtz–Fittig reaction is best for the formation of asymmetrical products if halide reactants are different in their relative chemical reactivities. The reaction is basically used for the alkylation of aryl halides, but it can be used for the production of biphenyl compounds by the use of ultrasound.
Fitting Reaction
Wurtz–Fittig reacts in two different ways. The first one is the one which is described as above and the other one can be defined as stated below:
When two molecules of aryl halide react with sodium metal in presence of dry ether to form diphenyl.
Except for sodium, many other metals can also be used in order to give rise to similar products. This includes potassium, iron, copper, and lithium. While using lithium, the reaction needs ultrasound presence, in order to obtain the product.
Mechanism of Wurtz–Fittig Reaction
In order to understand the Wurtz–Fittig reaction, let us take an example.
Consider the following generic reaction.
In this reaction, sodium metal reacts separately with two types of halide to form aryl sodium and alkyl sodium.
The more reactive alkyl halide forms an organo sodium first, and this reacts as a nucleophile with an aryl halide.
Mechanism of Wurtz–Fittig reaction is not certain as there are two approaches available to describe the mechanism of Wurtz–Fittig reaction and empirical evidence are available for both approaches. Both the approaches are listed below –
Radical mechanism
Organo-alkali mechanism
Radical Mechanism
The radical approach involves the sodium-mediated aryl radical and alkyl radical formation. According to this mechanism, sodium metal acts as a mediator and the formation of an alkyl radical and aryl radical takes place. Then, alkyl radical and aryl radical combine to form a substituted aromatic compound. This mechanism is supported by the formation of side products which cannot be explained by the organo-alkali mechanism. For example, Bachmann and Clarke found that in the reaction of sodium and chlorobenzene, one of the many side products is triphenylene whose formation can be explained by free radical mechanism only. Reaction mechanism is given below –
Organo-Alkali Mechanism
The organo-alkali approach involves the formation of an intermediate organo – alkali compound by reaction of an aryl halide with sodium metal. According to this approach, first aryl halide reacts with sodium metal and forms an organo-alkali compound, then nucleophilic attack of alkyl halide takes place. This mechanism is supported by indirect evidence such as many investigators observed that an organo-alkali intermediate is actually formed during the reaction. The reaction mechanism is given below –
Use of Other Metal in Place of Sodium
Wurtz–Fittig reactions can be carried out using other metals such as copper, iron, potassium, and lithium than sodium metal. When we use lithium in place of sodium, the reaction gives an appreciable yield, but the reaction takes place only under ultrasound. It takes place by a free radical mechanism.
Wurtz Reaction, Fittig Reaction, and Wurtz–Fittig Reaction
Generally, students get confused between Wurtz reaction, Fittig reaction, and Wurtz–Fittig reaction. So, we are giving here a comparative study of all these three reactions in a tabular form –
Applications of Wurtz–Fittig Reaction
Wurtz–Fittig reaction is useful in the laboratory for the synthesis of organosilicon compounds. For example, t-butyl trimethoxysilane can be prepared by Wurtz–Fittig reaction. In this 40% yield is obtained.
Applications of Wurtz–Fittig reactions are limited. It is not used at a large scale for industrial purposes. However, it is useful in the laboratory synthesis of substituted aromatic compounds.
The reaction doesn't have many applications. This is because of the side reaction, which further undergoes rearrangement and elimination. This is one of the major limitations of this reaction making it unsuitable for many production processes.
The production of organosilicon is done using this particular reaction although it is quite a big challenge to overcome the production in a larger quantity.
This was all about Wurtz–Fittig reaction.
FAQs on Wurtz - Fittig Reaction
1. What is the Wurtz-Fittig reaction as per the Class 12 syllabus?
The Wurtz-Fittig reaction is a name reaction in organic chemistry used to synthesise alkyl-substituted aromatic compounds. It involves the coupling of an aryl halide with an alkyl halide in the presence of sodium metal and dry ether as a solvent. This reaction forms a new carbon-carbon bond between the aromatic ring and the alkyl group. For example, reacting bromobenzene with ethyl bromide and sodium in dry ether yields ethylbenzene.
2. What are the essential reactants and conditions required for the Wurtz-Fittig reaction?
To carry out a successful Wurtz-Fittig reaction, the following components and conditions are essential:
- Aryl Halide: A halogen-substituted aromatic compound (e.g., bromobenzene, chlorobenzene).
- Alkyl Halide: A halogen-substituted alkane (e.g., chloroethane, iodomethane).
- Metallic Sodium: Acts as the coupling agent.
- Dry Ether: An anhydrous, aprotic solvent is crucial to prevent sodium from reacting with any moisture present.
3. How does the Wurtz-Fittig reaction mechanism work?
The exact mechanism of the Wurtz-Fittig reaction is not definitively established, but two primary pathways are proposed:
- Radical Mechanism: In this pathway, sodium metal donates an electron to both the alkyl halide and the aryl halide, forming an alkyl radical and an aryl radical. These two radicals then combine to form the final alkylarene product. The formation of side products like biphenyl (from two aryl radicals) and higher alkanes (from two alkyl radicals) supports this mechanism.
- Organo-Alkali Mechanism: This pathway suggests the formation of an organosodium intermediate. The aryl halide reacts with sodium to form an aryl sodium compound, which then acts as a nucleophile and attacks the alkyl halide to form the product.
4. What is the key difference between the Wurtz, Fittig, and Wurtz-Fittig reactions?
These three reactions are related coupling reactions but differ in their reactants:
- Wurtz Reaction: Involves the coupling of two alkyl halides with sodium in dry ether to form a higher, symmetrical alkane. (2 R-X → R-R)
- Fittig Reaction: Involves the coupling of two aryl halides with sodium in dry ether to form a biaryl compound, such as biphenyl. (2 Ar-X → Ar-Ar)
- Wurtz-Fittig Reaction: A hybrid reaction that couples one alkyl halide and one aryl halide using sodium in dry ether to form an alkyl-substituted aromatic compound. (Ar-X + R-X → Ar-R)
5. Why is dry ether used as a solvent in the Wurtz-Fittig reaction?
Using dry (anhydrous) ether is critical for the Wurtz-Fittig reaction because sodium metal is highly reactive. If any moisture (water) is present in the solvent, the sodium will react vigorously with it to form sodium hydroxide and hydrogen gas. This side reaction would consume the sodium, preventing it from participating in the intended coupling reaction with the halides, thus stopping or severely reducing the yield of the desired product.
6. What are the main limitations of the Wurtz-Fittig reaction?
The Wurtz-Fittig reaction has several limitations that restrict its synthetic utility. The most significant issue is the formation of unwanted side products. The alkyl halides can react with themselves (Wurtz reaction) and the aryl halides can react with themselves (Fittig reaction), leading to a mixture of products that is often difficult to separate. Furthermore, the reaction is susceptible to rearrangement and elimination side reactions, especially with bulky alkyl halides, which lowers the yield of the desired alkylarene.
7. Why is the Wurtz-Fittig reaction unsuitable for preparing compounds with tertiary alkyl groups?
The Wurtz-Fittig reaction is not suitable for tertiary alkyl halides due to steric hindrance. The bulky nature of a tertiary alkyl group makes it difficult for the nucleophilic attack (in the organo-alkali mechanism) or radical coupling to occur at the crowded carbon atom. Instead of substitution, tertiary alkyl halides preferentially undergo elimination reactions in the presence of the strongly basic conditions, leading to the formation of alkenes as the major product rather than the desired alkyl-substituted benzene.

















