
The specific latent heat of fusion of water is:
(A) $80{\text{ cal }}{{\text{g}}^{{\text{ - 1}}}}$
(B) $2260{\text{ J }}{{\text{g}}^{{\text{ - 1}}}}$
(C) $80{\text{ J }}{{\text{g}}^{{\text{ - 1}}}}$
(D) $3366{\text{ cal }}{{\text{g}}^{{\text{ - 1}}}}$
Answer
169.2k+ views
Hint: The specific latent heat of fusion of water is 334 Joules per gram. Convert it into calories per gram using the conversion 1 calorie = 4.184 Joules or 1 Joule = 0.239 calories.
Complete step by step solution
We know that the change of state from solid to liquid (or ice to water here) is termed as fusion. When a solid is heated, its temperature increases till it reaches the melting point of the solid, then for a while, the increase in temperature on applying heat stops. This is because the substance starts changing its state from solid to liquid, i.e. the solid substance starts melting. During change of state from one state to another, the temperature remains constant. In our case, when heat energy is added to ice at its melting point, i.e. at 0°C, it changes into the same mass of water at 0°C.
This happens because the heat applied at that time is used up in changing the state of the substance rather than in increasing the temperature of the substance. This heat energy, required to change the state of a substance is called latent heat. There are basically two types of latent heats, one for fusion and one for vaporization. In our question, we require the latent heat of fusion.
We know that the Latent heat of fusion of water is 334 Joules per gram or 334000 Joules per Kilogram. We will convert this into calories per gram to match an answer from the options.
\[
\because 1J = 0.239cal \\
\Rightarrow 1J/g = 0.239cal/g \\
\Rightarrow 334J/g = 334 \times 0.239cal/g \\
\Rightarrow 334J/g = 79.826cal/g \\
\Rightarrow 334J/g \approx 80cal/g \\
\]
Therefore, option (A): 80 cal g-1 is correct.
Note: Here, one should be careful not to confuse latent heat of fusion and specific latent heat of fusion. Latent heat of fusion is the amount of energy required to change the state of a given mass of substance from solid to liquid whereas the specific heat of fusion is the amount of energy required to change the state of a 1kg of substance from solid to liquid.
The relation between the two is ${L_f} = \dfrac{{{Q_f}}}{M}$.
where, $L_f$ is the specific latent heat of fusion of the substance
$Q_f$ is the latent heat of fusion of the substance
and M is the mass of the substance
Complete step by step solution
We know that the change of state from solid to liquid (or ice to water here) is termed as fusion. When a solid is heated, its temperature increases till it reaches the melting point of the solid, then for a while, the increase in temperature on applying heat stops. This is because the substance starts changing its state from solid to liquid, i.e. the solid substance starts melting. During change of state from one state to another, the temperature remains constant. In our case, when heat energy is added to ice at its melting point, i.e. at 0°C, it changes into the same mass of water at 0°C.
This happens because the heat applied at that time is used up in changing the state of the substance rather than in increasing the temperature of the substance. This heat energy, required to change the state of a substance is called latent heat. There are basically two types of latent heats, one for fusion and one for vaporization. In our question, we require the latent heat of fusion.
We know that the Latent heat of fusion of water is 334 Joules per gram or 334000 Joules per Kilogram. We will convert this into calories per gram to match an answer from the options.
\[
\because 1J = 0.239cal \\
\Rightarrow 1J/g = 0.239cal/g \\
\Rightarrow 334J/g = 334 \times 0.239cal/g \\
\Rightarrow 334J/g = 79.826cal/g \\
\Rightarrow 334J/g \approx 80cal/g \\
\]
Therefore, option (A): 80 cal g-1 is correct.
Note: Here, one should be careful not to confuse latent heat of fusion and specific latent heat of fusion. Latent heat of fusion is the amount of energy required to change the state of a given mass of substance from solid to liquid whereas the specific heat of fusion is the amount of energy required to change the state of a 1kg of substance from solid to liquid.
The relation between the two is ${L_f} = \dfrac{{{Q_f}}}{M}$.
where, $L_f$ is the specific latent heat of fusion of the substance
$Q_f$ is the latent heat of fusion of the substance
and M is the mass of the substance
Recently Updated Pages
Preparation of Hydrogen Gas: Methods & Uses Explained

Polymers in Chemistry: Definition, Types, Examples & Uses

P Block Elements: Definition, Groups, Trends & Properties for JEE/NEET

Order of Reaction in Chemistry: Definition, Formula & Examples

Hydrocarbons: Types, Formula, Structure & Examples Explained

Classification of Elements and Periodicity in Properties | Trends, Notes & FAQs

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

Uniform Acceleration

Displacement-Time Graph and Velocity-Time Graph for JEE

Atomic Structure - Electrons, Protons, Neutrons and Atomic Models

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Instantaneous Velocity - Formula based Examples for JEE

Other Pages
NCERT Solutions for Class 11 Physics Chapter 1 Units and Measurements

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 11 Physics Chapter 2 Motion In A Straight Line

Units and Measurements Class 11 Notes: CBSE Physics Chapter 1

Motion in a Straight Line Class 11 Notes: CBSE Physics Chapter 2

Important Questions for CBSE Class 11 Physics Chapter 1 - Units and Measurement
