

Introduction to Multiple and Submultiple Angles
Multiple and submultiple angles formula is a mathematics formula that provides the trigonometry ratios for determining various angles of the triangle. These types of formulas are important because they help provide information about the shape, size and location of a given triangle. In trigonometry, the three branches of trigonometry are named after the types of angles they measure: sine, cosine, and tangent. This article will provide you with information on how to work out the two or more different angles in a triangle using multiple and submultiple angles formula.
Meaning of Multiple and Sub Multiple Angles
Let A be any angle . For this angle A , the multiple angles will be 2A , 3A , 4A and so on. To make it more easy to understand, we can assume that what the answer will be if we multiply 2 in A, which is our angle. The answer will be 2A. Again if we multiply 3 with A, the answer will be 3A. Again if we multiply 4 with A, the answer will be 4A . In the same way we can find multiple angles of any given angle.
As we have clearly discussed, the multiple angles of any given angle . Now let us discuss what the sub multiple angles are.
Let there be an angle A, the sub multiple angles for this will be $\dfrac{A}{2}$, $\dfrac{A}{3}$, $\dfrac{A}{4}$ and so on.
For better understanding we will take a simple example . What will be the answer if we multiply $\dfrac{1}{2}$ with A, which is a given angle. The answer will be $\dfrac{A}{2}$. In the same way if we multiply $\dfrac{1}{3}$ with A, the answer will be $\dfrac{A}{3}$. And so on.
For better understanding, find the multiple angles of given angles:
Q 1. What will be the sub multiple angle of X ?
(A) $\dfrac{X}{2}$
(B) $\dfrac{D}{2}$
(C) 2X
(D) $\dfrac{D}{2}$
Ans: $\dfrac{X}{2}$
Q 2. What will be the sub multiple angle of D ?
(A) $\dfrac{X}{2}$
(B) $\dfrac{D}{2}$
(C) 2X
(D) $\dfrac{G}{2}$
Ans: $\dfrac{D}{2}$
Explanation of Quadrants
When axis X and Y intersect each other at 90 degrees, we get four regions. These regions are called quadrants.

Quadrants
As shown above in figure, there are four regions. The upper right part is called the first quadrant, and it is the positive region. The upper left region is called the second quadrant, and it has minus and positive signs. The lower left region is called the third quadrant, and it has a minus sign, and the lower right region is called the fourth quadrant, and it has positive and negative signs.
Trigonometric Ratios
In a right angle triangle, the base of the triangle is called “base”. In the figure below, OA is the base. The standing straight line of the triangle is called the perpendicular of the triangle. In the below figure AB is the perpendicular of the triangle.This AB and OA make 90 ° angle. And OB is the hypotenuse of the triangle.

Right angled triangle
$\sin \theta=\dfrac{\text { opposite }}{\text { hypotenuse }}=\dfrac{A B}{O B}$
$\cos \theta=\dfrac{\text { adjacent }}{\text { hypotenuse }}=\dfrac{O A}{O B}$
$\tan \theta=\dfrac{\text { opposite }}{\text { adjacent }}=\dfrac{A B}{O A}$
$\operatorname{cosec} \theta=\dfrac{1}{\sin \theta}=\dfrac{O B}{A B}$
$\sec \theta=\dfrac{1}{\cos \theta}=\dfrac{O B}{O A}$
$\cot \theta=\dfrac{1}{\tan \theta}=\dfrac{O A}{A B}$
Trigonometry Table
As shown in the figure below, you can see the table. It is called a Trigonometry table. We can also call it a table of angles. The value of sin 0 will be 0. The value of sin 30 will be $\dfrac{1}{2}$. The value of cos 0 will be 1. The value of tan 0 will be 0, the value of cot 0 will be infinity. The value of sec 0 will be 1. The value of cosec 0 will be infinity. In the same way you can read this table.

Table of Angle
Trigonometry Ratios Formulas Based on Multiple and Submultiple Angles
There are some basic formulas given below for multiple angles.
$\sin (A \pm B)=\sin A \cos B \pm \cos A \sin B$
$\cos (A \pm B)=\cos A \cos B \pm \sin A \sin B$
$\tan (A \pm B)=\dfrac{\tan A \pm \tan B}{1 \pm \tan A \tan B}$
$\sin 2 A=2 \sin A \cos A=\dfrac{2 \tan A}{1+\tan ^2 A}$
$\cos 2 A=\cos ^2 A-\sin ^2 A=\dfrac{1-\tan ^2 A}{1+\tan ^2 A}=2 \cos ^2 A-1=1-2 \sin ^2 A$
$\sin 3 A=3 \sin A-4 \sin ^3 A$
$\cos 3 A=4 \cos ^3 A-3 \cos A$
$\tan 3 A=\dfrac{3 \tan A-\tan ^3 A}{\dfrac{1-3 \tan ^2 A}{A}}$
$\sin \dfrac{A}{2}=\sqrt{\dfrac{1-\cos A}{2}}$
$\cos \dfrac{A}{2}=\sqrt{\dfrac{1+\cos A}{2}}$
$\tan \dfrac{A}{2}=\sqrt{\dfrac{1-\cos A}{1+\cos A}}=\dfrac{1-\cos A}{\sin A}=\dfrac{\sin A}{1+\cos A}$
$\sin C+\sin D=2 \sin \dfrac{C+D}{2} \cos \dfrac{C-D}{2}$
$\sin C-\sin D=2 \cos \dfrac{C+D}{2} \sin \dfrac{C-D}{2}$
$\cos C+\cos D=2 \cos \dfrac{C+D}{2} \cos \dfrac{C-D}{2}$
$\cos C-\cos D=2 \sin \dfrac{C+D}{2} \sin \dfrac{D-C}{2}$
$\tan C+\tan D=\dfrac{\sin (C+D)}{\cos C \cos D}$
$\sin (A+B) \sin (A-B)=\sin ^2 A-\sin ^2 B$
$\cos (A+B) \cos (A-B)=\cos ^2 A-\sin ^2 B$
$\sin ^2 A=\dfrac{1}{2}(1-\cos 2 A)$
$ \cos ^2 A=\dfrac{1}{2}(1+\cos 2 A)$
$\tan ^2 A=\dfrac{1-\cos 2 A}{1+\cos 2 A}$
$\sin ^3 A=\dfrac{3 \sin A-\sin 3 A}{4}$
$\cos ^3 A=\dfrac{3 \cos A+\cos 3 A}{4}$
Solved Examples
For better understanding, find the multiple angles of given angles.
Q 1. What will be the multiple angle of X?
(A) 2D
(B) 5G
(C) 2X
(D) 4B
Ans: (C) 2X
In the question X is the angle. So, obviously multiple angle of "X" will contain "X" in the answer. In the options given above only the option "(C)" contains "X" . So it will be the answer.
Q 2. What will be the multiple angles of D?
(A) 2D
(B) X
(C) 2X
(D) 4B
Ans: (A) 2D
In the question D is the angle. So, obviously multiple angle of "D" will contain "D" in the answer. In the options given above only the option "(A)" contains "D" . So it will be the answer.
Q 3. What will be the multiple angle of B?
(A) 2D
(B) X
(C) 2X
(D) 4B
Ans: (D) 4B
In question B is the angle. So, obviously multiple angle of "B" will contain "B" in the answer. In the options given above only the option "(D)" contains "B" . So it will be the answer.
Practice Questions
Q 1. What will be the multiple angles of G?
Ans: 2G
Q 2. What will be the multiple angle of Z?
Ans: 2Z, 3Z, 4Z
Summary
So in this chapter you got to know about trigonometry and multiple and submultiple angles formulas in a very easy way. Also, we learned about the quadrants in trigonometry, what they are and how to name them along with the trigonometric tables and ratios. We further learned about them by solving numerous questions and practicing along with some solved examples. By solving questions, you can develop a keen understanding of the topic, which will further help you with trigonometry ahead in higher classes.
FAQs on Multiple and Submultiple Angles Formula
1. What are multiple and submultiple angles in trigonometry?
In trigonometry, multiple and submultiple angles are derived from a given angle, let's say 'A'.
- A multiple angle is an integer multiple of the angle A, such as 2A, 3A, 4A, and so on. For example, if A = 30°, then 2A = 60° is a multiple angle.
- A submultiple angle is a fraction of the angle A, such as A/2, A/3, A/4, and so on. For instance, if A = 60°, then A/2 = 30° is a submultiple angle.
These concepts are crucial for expressing trigonometric functions of one angle in terms of functions of another related angle.
2. What are the essential formulas for multiple angles like 2A and 3A?
The most commonly used multiple angle formulas are for the angles 2A and 3A. They allow us to find the trigonometric values for these angles if the values for angle A are known.
For angle 2A:
- sin(2A) = 2 sin(A) cos(A)
- cos(2A) = cos²(A) - sin²(A) = 2cos²(A) - 1 = 1 - 2sin²(A)
- tan(2A) = (2 tan(A)) / (1 - tan²(A))
For angle 3A:
- sin(3A) = 3 sin(A) - 4 sin³(A)
- cos(3A) = 4 cos³(A) - 3 cos(A)
- tan(3A) = (3 tan(A) - tan³(A)) / (1 - 3 tan²(A))
3. How are the formulas for submultiple angles (like A/2) expressed?
Submultiple angle formulas, often called half-angle formulas, express trigonometric functions of A/2 in terms of the cosine of angle A. These are particularly useful for finding the values of angles like 15° or 22.5°.
- sin(A/2) = ±√[(1 - cos A) / 2]
- cos(A/2) = ±√[(1 + cos A) / 2]
- tan(A/2) = ±√[(1 - cos A) / (1 + cos A)]
The choice of the plus (+) or minus (-) sign depends on the quadrant in which the angle A/2 lies.
4. How are multiple angle formulas, such as for sin(2A), derived?
Multiple angle formulas are not arbitrary; they are derived directly from the compound angle (or sum) formulas. For example, to derive the formula for sin(2A):
- Start with the sum formula: sin(A + B) = sin(A)cos(B) + cos(A)sin(B).
- To get sin(2A), we can write it as sin(A + A).
- Now, substitute 'A' for 'B' in the sum formula: sin(A + A) = sin(A)cos(A) + cos(A)sin(A).
- By combining the like terms, we get the final result: sin(2A) = 2 sin(A)cos(A).
A similar process of substitution is used to derive all other multiple and submultiple angle formulas.
5. What is the practical importance of using multiple and submultiple angle formulas?
These formulas are fundamental tools in mathematics and science for several reasons:
- Simplifying Expressions: They help simplify complex trigonometric expressions into more manageable forms.
- Solving Equations: They are essential for solving trigonometric equations where different angle multiples are involved.
- Integration and Calculus: In calculus, they are used to integrate powers of sine and cosine by converting them into linear trigonometric functions (e.g., using cos(2A) to simplify ∫cos²(x) dx).
- Finding Exact Values: Submultiple angle formulas allow us to calculate exact trigonometric values for angles that are not standard (like 15°, 22.5°, 75°) by using the known values of standard angles (30°, 45°, 60°).
6. Is sin(2A) equivalent to 2sin(A)? Clarify this common misconception.
No, sin(2A) is not the same as 2sin(A). This is a very common mistake. The 'sin' is a function, not a variable that can be factored out. We can prove this with a simple example:
- Let A = 30°.
- Then, sin(2A) = sin(2 × 30°) = sin(60°) = √3 / 2 ≈ 0.866.
- However, 2sin(A) = 2 × sin(30°) = 2 × (1/2) = 1.
As you can see, 0.866 ≠ 1. The correct relationship is given by the double angle formula: sin(2A) = 2sin(A)cos(A).
7. How do the formulas for cos(2A) help in expressing powers of sine and cosine?
The various forms of the cos(2A) formula are incredibly useful for reducing the power of trigonometric functions, which is a key technique in calculus. These are often called power-reducing formulas.
- From the formula cos(2A) = 1 - 2sin²(A), we can rearrange it to get: sin²(A) = (1 - cos(2A)) / 2. This changes a squared term into a term with a power of one.
- Similarly, from cos(2A) = 2cos²(A) - 1, we can rearrange it to get: cos²(A) = (1 + cos(2A)) / 2.
This transformation is vital for simplifying integrals and solving certain types of differential equations.





