RD Sharma Solutions for Class 12 Maths Chapter 16 - Tangents and Normals - Free PDF Download
FAQs on RD Sharma Class 12 Maths Solutions Chapter 16 - Tangents and Normals
1. How do Vedantu's solutions for RD Sharma Class 12 Chapter 16 help in solving problems on tangents and normals?
Vedantu's solutions for RD Sharma Class 12 Chapter 16 provide detailed, step-by-step methods for every problem. They break down complex questions into simple, understandable steps, ensuring students can follow the correct procedure for finding the equations of tangents and normals, angles between curves, and other related concepts as per the 2025-26 CBSE syllabus.
2. What is the first step to find the equation of a tangent to a curve y = f(x) at a given point (x₁, y₁)?
The first and most crucial step, as demonstrated in the RD Sharma solutions, is to find the derivative of the function, which is dy/dx or f'(x). This derivative represents the formula for the slope of the tangent at any point on the curve. You then substitute the given point (x₁, y₁) into the derivative to find the specific slope at that point.
3. How do you determine the equation of a normal to a curve at a specific point?
To find the equation of the normal, you follow these steps, which are clearly outlined in the RD Sharma solutions for Chapter 16:
- First, calculate the slope of the tangent (m_t) at the given point by finding dy/dx.
- Next, find the slope of the normal (m_n) using the relation m_n = -1 / m_t.
- Finally, use the point-slope form, y - y₁ = m_n(x - x₁), to get the final equation of the normal.
4. Why is the derivative dy/dx fundamental to finding the slope of the tangent?
The derivative dy/dx represents the instantaneous rate of change of y with respect to x. Geometrically, this rate of change at a specific point is the slope of the line that just touches the curve at that point, which is the tangent. The RD Sharma solutions build upon this core concept of Applications of Derivatives, using it as the foundation for every problem involving tangents.
5. What is a common mistake when finding the slope of the normal, and how do the solutions help prevent it?
A common mistake is forgetting that the slope of the normal is the negative reciprocal of the tangent's slope. Students often incorrectly use the same slope as the tangent or just change its sign. The RD Sharma solutions reinforce the correct formula, m_normal = -1 / m_tangent, in every relevant problem, helping students avoid this critical error and understand the perpendicular relationship between the two lines.
6. How do the RD Sharma solutions handle problems where the tangent is parallel to the x-axis or y-axis?
The solutions provide a clear method for these special cases:
- If a tangent is parallel to the x-axis, its slope is 0. So, we set dy/dx = 0 and solve for the coordinates of the point.
- If a tangent is parallel to the y-axis (or perpendicular to the x-axis), its slope is undefined. This occurs when the denominator of dy/dx is zero. We solve for the point where dx/dy = 0.
7. Why is it beneficial to practice from RD Sharma for Tangents and Normals after completing NCERT?
While NCERT builds the foundation, RD Sharma provides a wider variety of problems, including more complex and Higher Order Thinking Skills (HOTS) questions. Practising with RD Sharma Solutions for Chapter 16 helps students master different problem formats, handle tricky calculations, and build the speed and confidence needed for the CBSE Class 12 board exams.
8. How is the concept of tangents used to find the angle of intersection between two curves?
The angle of intersection between two curves at a point is defined as the angle between their tangents at that point. The RD Sharma solutions show that to find this angle (θ), you must:
- Find the slopes of the tangents for both curves at the intersection point (let's call them m₁ and m₂).
- Use the formula tan(θ) = |(m₁ - m₂)/(1 + m₁m₂)|.
- This method effectively applies the core concept of tangents to a more complex problem scenario.

















