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RD Sharma Class 12 Maths Solutions Chapter 32 - Mean and Variance of a Random Variable

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RD Sharma Solutions for Class 12 Maths - Mean and Variance of a Random Variable - Free PDF Download

RD Sharma Solutions of Class 12 Maths Chapter 32 Mean and Variance of a Random Variable are provided at Vedantu for free. We offer RD Sharma Solutions of Class 12 Maths Chapter 32 PDF that consist of logical questions along with resolved examples to help students understand the definitions and the topics clearly. RD Sharma Class 12 Mean And Variance of a Random Variable covers issues pertaining to the mean and standard deviation. These ideas have been devised by our experts in a precise, systematic, and informative manner.


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Class 12 RD Sharma Textbook Solutions Chapter 32 - Mean and Variance of a Random Variable

Vedantu offers the RD Sharma Class 12  Maths Solutions Chapter 32 - Mean And Variance Of A Random Variable to the students which are completely free of cost. These RD Sharma Class 12 Maths Solutions Chapter 32 - Mean And Variance Of A Random Variable are provided in PDF format, which can be downloaded by the students to study offline. 

The subject matter experts at Vedantu had prepared these solutions: The RD Sharma Class 12 Maths Solutions Chapter 32- Mean And Variance Of A Random Variable appropriately. All these solutions are made concerning the latest NCERT syllabus and guidelines. These solutions are made to help and guide students and make them prepared for their examinations. These solutions assist students in their homework and assignments. Students can top the final exams and ace the subject by practising these solutions. 

Important Topics in RD Sharma Solutions of Class 12 Maths Chapter 32

RD Sharma Class 12 Mean And Variance of a Random Variable will help you to understand important concepts such as the distribution of probability, the mean of a discrete random variable, the variance of a discrete random variable, and more in a very simplified and organized way.

Exercises in RD Sharma Class 12 Chapter 32 are

Preparation Tips

  • It's a smart idea to take daily exercise while studying. A short stroll, or more physical exercise, will keep the blood pumping to make sure you are able to focus.

  • Some of us need absolutely cleanliness and order to focus, while others excel in a more cluttered environment. Take care of what is working for you, and take the time to make things right.

  • Try not to feel bad for going out and enjoying the sunshine. Note that vitamin D is essential for a healthy brain.

Conclusion

RD Sharma Solutions of Class 12 Maths Chapter 32 are given here. To help students grasp the idea clearly, we are providing RD Sharma Class 12 Chapter 32 solutions that consist of conceptual challenges along with examples that have been resolved. Our subject matter experts have prepared the solutions and even planned the problems of RD Sharma Class 12 Chapter 32 so that you can have a lot of fun when you solve them. Students should be vigilant with this chapter as variance and mean is one of the most important subjects to study in mathematics. RD Sharma Solutions of Class 12 Maths Chapter 32 will help students learn better skills and help them study successfully for the exams.

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FAQs on RD Sharma Class 12 Maths Solutions Chapter 32 - Mean and Variance of a Random Variable

1. Why should a Class 12 student use RD Sharma solutions for the chapter on Mean and Variance of a Random Variable?

RD Sharma solutions offer a comprehensive set of well-graded problems for this chapter. They provide detailed, step-by-step explanations that go beyond basic NCERT exercises, helping students build a strong foundation and tackle complex questions. This is crucial for mastering the application of formulas for mean E(X) and variance Var(X).

2. How do the RD Sharma solutions for Chapter 32 help in preparing for the CBSE Class 12 board exams (2025-26)?

These solutions are aligned with the CBSE syllabus and help students master the expected problem types. By practising the variety of questions in RD Sharma, students can improve their speed and accuracy in calculating mean and variance. The solutions demonstrate the proper format for writing answers, which is essential for scoring full marks in board exams.

3. What is the step-by-step method shown in RD Sharma solutions to find the mean (or expected value) of a discrete random variable?

The solutions consistently follow a clear method:

  • First, identify all possible values of the random variable X (let's say x₁, x₂, ..., xₙ).
  • Next, calculate the probability P(X=xᵢ) for each value.
  • Construct a probability distribution table with values of X and their corresponding probabilities P(X).
  • Finally, calculate the mean or expected value, E(X), using the formula E(X) = ΣxᵢP(xᵢ).

4. How do you calculate the variance of a random variable using the formula Var(X) = E(X²) - [E(X)]², as explained in RD Sharma solutions?

The RD Sharma solutions break this down into a manageable process. After finding the mean E(X), you need to:

  • Calculate E(X²) by using the formula E(X²) = Σxᵢ²P(xᵢ). This involves squaring each value of the random variable, multiplying by its probability, and summing the results.
  • Square the mean that you calculated earlier to get [E(X)]².
  • Substitute these two values into the variance formula: Var(X) = E(X²) - [E(X)]² to get the final answer.

5. What is a common mistake to avoid when calculating variance, and how do RD Sharma solutions help prevent it?

A very common mistake is confusing E(X²) (the mean of the squares of the random variable) with [E(X)]² (the square of the mean). The RD Sharma solutions clearly separate these two calculations. By showing the step-by-step process of first finding E(X), then finding E(X²), and only then subtracting, they help reinforce the correct operational order and prevent this conceptual error.

6. Why is creating a correct probability distribution table the most critical first step before finding mean and variance, as emphasized in RD Sharma solutions?

The entire calculation of mean and variance depends on the probability distribution table. If the probabilities are incorrect or do not sum to 1, every subsequent calculation, including E(X) and Var(X), will be wrong. RD Sharma solutions consistently start with building this table, highlighting its foundational importance for ensuring the accuracy of the final answer.

7. How do the solved examples in RD Sharma for this chapter clarify the practical difference between E(X²) and [E(X)]²?

The solved examples provide concrete numerical context. When you solve a problem, you might calculate a mean E(X) = 2.5, which makes [E(X)]² = 6.25. Then, you calculate E(X²) by summing the xᵢ²P(xᵢ) terms, which might result in a value like E(X²) = 7.5. By working through these distinct numerical calculations for the same problem, the abstract difference between the two terms becomes clear and tangible.

8. Are the problems in RD Sharma Chapter 32 sufficient for questions on this topic in competitive exams like JEE?

While RD Sharma provides an excellent foundation and is more extensive than NCERT, competitive exams like JEE Main often involve more complex applications. The solutions build the core skills needed, but students aiming for top ranks in JEE should supplement their practice with previous year's JEE papers and mock tests that focus on advanced problem-solving strategies for this topic.