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RD Sharma Class 12 Solutions Chapter 18 - Maxima and Minima (Ex 18.2) Exercise 18.2

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RD Sharma Class 12 Solutions Chapter 18 - Maxima and Minima (Ex 18.2) Exercise 18.2 - Free PDF

Free PDF of RD Sharma Class 12 Solutions Chapter 18 – Maxima and Minima Exercise 18.2 solved by expert Mathematics teachers is available for download on Vedantu.com. All Chapter 18 – Maxima and Minima Ex 18.2 Questions with Solutions for RD Sharma Class 12 Maths will help you to revise the complete syllabus and score more marks. Register for online coaching for IIT JEE (Mains & Advanced) and other engineering entrance exams on Vedantu.com.

 

Maxima and minima are some of the important concepts taught in Class 12. It is Chapter 18 in RD Sharma’s book while in the NCERT textbook it is discussed in depth under Chapter 6 called application of derivatives.

 

As this concept is extremely vast, RD Sharma has given it utmost importance by separating it from the rest of the concepts. Maxima and minima are the largest and smallest values of the function, either within a given range or on the entire domain. It teaches in-depth about the method to calculate the maximum and the minimum value of a function that is the highest and the lowest points in the graph.

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RD Sharma Class 12 Solutions Chapter 18 – Maxima and Minima

Important Definitions Covered in This Chapter

1. Let f be a function defined on an interval I. Then,


(a) f is said to have a maximum value in I, if there exists a point c in I such that f(c)>f(x), for all x ∈ I. The number f(c) is called the maximum value of f in I and the point c is called a point of maximum value of f in I.


(b) f is said to have a minimum value in I, if there exists a point c in I such that f(c) < f(x), for all x ∈ I. The number f(c), in this case, is called the minimum value of f in I and the point c, in this case, is called a point of minimum value of f in I.


(c) f is said to have an extreme value in I if there exists a point c in I such that f(c) is either a maximum value or a minimum value of f in I. The number f(c), in this case, is called an extreme value of f in I and the point c is called an extreme point.


2.  Let f be a real-valued function and let c be an interior point in the domain of f. Then,


(a) c is called a point of local maxima if there is an h > 0 such that f(c) ≥ f(x), for all x in (c – h, c + h) x ≠ c, the value f(c) is called the local maximum value of f.


(b) c is called a point of local minima if there is an h > 0 such that f(c) ≤ f(x), for all x in (c – h, c + h), the value f(c) is called the local minimum value of f .


Important Theorems 

Let f be a function defined on an open interval I. Suppose c ∈ I be any point. If f has a local maxima or local minima at x = c, then either f ′(c) = 0 or f is not differentiable at c.


(First Derivative Test) Let f be a function defined on an open interval I. Let f be continuous at a critical point c in I. Then,


(i) If f ′(x) changes sign from positive to negative as x increases through c, i.e., if f ′(x) > 0 at every point sufficiently close to and to the left of c, and f ′(x) < 0 at every point sufficiently close to and to the right of c, then c is a point of local maxima.


(ii) If f ′(x) changes sign from negative to positive as x increases through c, i.e., if f ′(x) < 0 at every point sufficiently close to and to the left of c, and f′(x) > 0 at every point sufficiently close to and to the right of c, then c is a point of local minima.


(iii) If f ′(x) does not change sign as x increases through c, then c is neither a point of local maxima nor a point of local minima. In fact, such a point is called point of inflection.

(Second Derivative Test) Let f be a function defined on an interval I and c ∈ I. Let f be twice differentiable at c. Then,


(i) x = c is a point of local maxima if f ′(c) = 0 and f ″(c) < 0. The value f(c) is the local maximum value of f.


(ii) x = c is a point of local minima if f′(c)=0 and f″(c)>0. In this case, f(c) is the local minimum value of f.


(iii) The test fails if f ′(c) = 0 and f ″(c) = 0.


Theorem: Let f be a continuous function on an interval I = [a, b]. Then, f has the absolute maximum value and f attains it at least once in I. Also, f has the absolute minimum value and attains it at least once in I.


Theorem:  Let f be a differentiable function on a closed interval I and let c be any interior point of I. Then,


(i) f ′(c) = 0 if f attains its absolute maximum value at c.


(ii) f ′(c) = 0 if f attains its absolute minimum value at c.

 


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FAQs on RD Sharma Class 12 Solutions Chapter 18 - Maxima and Minima (Ex 18.2) Exercise 18.2

1. What specific concepts of Maxima and Minima are covered in RD Sharma Class 12 Maths Exercise 18.2?

Exercise 18.2 of RD Sharma Class 12 Maths primarily focuses on the application of the Second Derivative Test to find local maxima and local minima of a function. The problems in this exercise require students to find critical points by setting the first derivative to zero (f'(x) = 0) and then use the sign of the second derivative (f''(x)) at those points to classify them.

2. Are the questions in RD Sharma for Chapter 18, Maxima and Minima, considered difficult?

The questions in RD Sharma's Chapter 18 are designed to build a strong conceptual foundation. While some problems, particularly in later exercises, can be more challenging than NCERT questions, they follow a logical progression. Exercise 18.2 provides essential practice to master the core methods, ensuring students are well-prepared for the variety of questions they might face in CBSE board exams.

3. How can using Vedantu's RD Sharma Solutions for Ex 18.2 help improve my board exam score?

Vedantu's solutions help improve scores by providing clear, step-by-step methodologies that align with the CBSE marking scheme. By studying these solutions, you learn how to correctly apply the First and Second Derivative Tests, how to present your answers systematically, and how to verify your results, which helps in minimising errors and maximising marks in the exam.

4. How do the problems in RD Sharma Exercise 18.2 differ from the questions in the NCERT textbook for Maxima and Minima?

While the NCERT textbook establishes the fundamental concepts and theorems of Maxima and Minima, RD Sharma's Exercise 18.2 provides a more extensive set of problems for practice. It often includes a wider variety of functions and scenarios, which helps in testing a student's grasp of the Second Derivative Test across different contexts, building proficiency beyond the basic syllabus requirements.

5. What is the correct way to use these RD Sharma solutions for effective learning?

The most effective method is to first attempt to solve the problems in Exercise 18.2 on your own. Use the solutions not to copy the answer, but as a tool for verification or guidance when you are stuck. This approach promotes active learning by helping you identify specific steps where you went wrong, thereby strengthening your conceptual understanding of finding maxima and minima.

6. What common pitfalls should I watch out for when solving problems in Exercise 18.2, and how do these solutions help?

A common pitfall is the case where the Second Derivative Test fails (i.e., f''(c) = 0). Students may get stuck or draw the wrong conclusion. The solutions demonstrate how to proceed in such cases by reverting to the First Derivative Test. They also help in avoiding common algebraic or differentiation errors by providing a clear, accurate reference for each step.

7. Are these solutions for RD Sharma Class 12 Chapter 18 updated for the latest 2025-26 CBSE syllabus?

Yes, all solutions provided by Vedantu for RD Sharma Class 12 Maths are meticulously curated by subject matter experts to be fully compliant with the latest CBSE syllabus for the 2025-26 academic session. They cover all the required methods and concepts for the topic of Maxima and Minima as prescribed by the board.